In a given frequency distribution,the respective values of mean and median are $21$ and $22$. The value of mode is

Let $a_1, a_2, \dots, a_{101}$ be a group of real numbers such that $a_i > a_{i+1}$ for all values of $i$ and the mean square deviation of the group is minimum about the number $a_{51}$. Then the mode of the group will be:

If the mode of a distribution is $18$ and the mean is $24$,then what is the median?

Consider the following frequency distribution:

Class	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$a$	$b$	$12$	$9$	$5$

If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$

The mode of the following frequency distribution is:

Class	$0-5$	$5-10$	$10-15$	$15-20$	$20-25$	$25-30$
Frequency $(f_i)$	$3$	$4$	$7$	$11$	$2$	$5$

Find the mode of the following distribution:

Marks	$4$	$5$	$6$	$7$	$8$
No. of students	$6$	$7$	$10$	$8$	$3$